物理化学052.ppt
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1、1,例题,例3.在一抽成真空的容器中单独放有NH4Cl(s),在340oC时分解反应NH4Cl(s)=NH3(g)+HCl(g)的平衡压力P1=104.6kPa;同样条件下,若单独放有NH4I(s),分解反应NH4I(s)=NH3(g)+HI(g)的平衡压力P2=18.85kPa。求NH4Cl(s)与NH4I(s)两种纯固态物质同时存在,加热到340oC,当上述两个反应都达到平衡时,系统的总压为多大?设HI(g)不分解,两个盐类不形成固态溶液。,2,Answer 1,NH4Cl(s)alone:NH4Cl(s)=NH3(g)+HCl(g)P(NH3)=P(HCl)=P1/2NH4I(s)alo
2、ne:NH4I(s)=NH3(g)+HI(g)P(NH3)=P(HI)=P2/2,3,When NH4Cl(ammonium chloride)and NH4I(ammonium iodide)coexist in the system,the partial pressure(分压)of ammonia(NH3)gas must accord with both two equilibrium mentioned above.If the partial pressure is P(NH3)for NH3(g),P(HCl)for HCl(g)and P(HI)for HI,So(1)(2)
3、and P(NH3)=P(HCl)+P(HI)(3)The answer is P(total)=P(NH3)+P(HCl)+P(HI)=106.3kPa,4,Answer 2,Let x and y denote the amounts of HCl and HI when the two equilibrium coexisted in the reaction system.So the amount of NH3 in the system must be x+y and the total amounts of three gas is 2(x+y).Thus,the partial
4、 pressure of NH3 is and,5,(we can see the partial pressure of P(NH3)=P(HCl)+P(HI)X=30.83y P(total)=106.3kPa,6,Key problem in this example,1.The partial pressure is a intensive variable(强度变量),and the amount of species is extensive variable(广度变量)2.Equilibrium constant for heterogeneous reactions(复相反应的
5、平衡常数)3.The calculate rule for the equilibria coexisted in a system(同时平衡的计算原则),7,Review,1 The criterion of a spontaneous chemical reaction2 The description of an equilibrium of reaction3 The isothermal(constant temperature)equation,8,Review,1 Several symbols1The Gibbs energy of a reaction system,G 2T
6、he reaction Gibbs energy:rGm=(G/)P,T3 The standard reaction Gibbs Energy4 is the Gibbs energy of mixing A and B5 Standard Gibbs energy of formation,9,2 Several relations:1 relation of reaction Gibbs energy(rGm)to the chemical potentials of the species,rGm=products-reactants2 The standard equilibrium
7、 constant(K)and the standard reaction Gibbs energy=-RT In Ko3 general expression for rGm at an arbitrary stage of the reaction,rGm=+RT In Q,10,Review,5thermodynamic equilibrium constant,(热力学平衡常数)can expressed in terms of activities(or fugacities):K for Perfect gas reaction,solution reaction and hete
8、rogeneous reaction has different form.6 in terms of standard Gibbs energies of formation,11,The content for this class,1The standard Gibbs energy of reaction in solution 2 The response of equilibria to the conditions1 How equilibria respond to pressure?2The effect of inert gas on equilibria3 Le Chat
9、eliers principle4The response of equilibria to temperature(van t Hoff equation)3 The coexist equilibrium,12,1 The standard Gibbs energy of reaction in solution,(1)Because the value of standard Gibbs energy formation(标准生成吉布斯自由能)is for a pure species,so the value of the standard reaction Gibbs energy(
10、反应的标准吉布斯自由能变)indicated that the standard state of each reactant and product is in the pure state.,13,The standard state for the species in solution reaction maybe not the pure state.(1)The solution need not distinguish solvent(溶剂)and solute(溶质)Equation(1)can be used to calculate the(2)The solvent an
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